Table 6-16 Subnets for the
192.168.1.0 /24 Network with 2 Borrowed Bits
Subnet
|
Network
Address
|
Host Range
|
Broadcast
Address
|
|
|
|
|
|
|
|
|
0
|
192.168.1.0/26
|
192.168.1.1–192.168.1.62
|
192.168.1.63
|
|
|
|
|
1
|
192.168.1.64/26
|
192.168.1.65–192.168.1.126
|
192.168.1.127
|
|
|
|
|
2
|
192.168.1.128/26
|
192.168.1.129–192.168.1.190
|
192.168.1.191
|
|
|
|
|
3
|
192.168.1.192/26
|
192.168.1.193–192.168.1.254
|
192.168.1.255
|
|
|
|
|
Calculate the number of subnets with
this formula:
22 = 4 subnets
To calculate the number of hosts,
begin by examining the last octet. Notice these subnets:
Subnet 1: 0 = 00000000
Subnet 2: 64 = 01000000
Subnet 3: 128 = 10000000
Subnet 4: 192 = 11000000
Apply the host calculation formula:
26 – 2 = 62
hosts per subnet
Creating Six
Subnets
Consider
the example in Figure 6-20 with five LANs and a WAN, for a total of six
net-works. The network information for this example is shown in Table 6-17, and
the calcula-tions follow.
Table 6-17 Subnets for the
192.168.1.0 /24 Network with 3 Borrowed Bits
Subnet
|
Network
Address
|
Host Range
|
Broadcast
Address
|
|
|
|
|
|
|
|
|
0
|
192.168.1.0/27
|
192.168.1.1–192.168.1.30
|
192.168.1.31
|
|
|
|
|
1
|
192.168.1.32/27
|
192.168.1.33–192.168.1.62
|
192.168.1.63
|
|
|
|
|
2
|
192.168.1.64/27
|
192.168.1.65–192.168.1.94
|
192.168.1.95
|
|
|
|
|
3
|
192.168.1.96/27
|
192.168.1.97–192.168.1.126
|
192.168.1.127
|
|
|
|
|
4
|
192.168.1.128/27
|
192.168.1.129–192.168.1.158
|
192.168.1.159
|
|
|
|
|
5
|
192.168.1.160/27
|
192.168.1.161–192.168.1.190
|
192.168.1.191
|
|
|
|
|
6
|
192.168.1.192/27
|
192.168.1.193–192.168.1.222
|
192.168.1.223
|
|
|
|
|
7
|
192.168.1.224/27
|
192.168.1.225–192.168.1.254
|
192.168.1.255
|
|
|
|
|
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