Table 6-15 Subnets for the
192.168.1.0 /24 Network with 1 Borrowed Bit
Subnet
|
Network
Address
|
Host Range
|
Broadcast
Address
|
|
|
|
|
|
|
|
|
1
|
192.168.1.0/25
|
192.168.1.1–192.168.1.126
|
192.168.1.127
|
|
|
|
|
2
|
192.168.1.128/25
|
192.168.1.129–192.168.1.254
|
192.168.1.255
|
|
|
|
|
Use this formula to calculate the
number of subnets:
2n, where n
= the number of bits borrowed
In the example of Figure 6-18 and
Table 6-15, the calculation is
21 = 2 subnets
For
each subnet, examine the last octet of the subnet address in binary. The values
in these octets for the two networks are
Subnet 1: 00000000 = 0
Subnet 2: 10000000 = 128
To
calculate the number of hosts per network, you use the formula of 2n
– 2, where n = the number of bits left for hosts.
Applying
this formula to the two-subnet example in Figure 6-18 and Table 6-15, 27
– 2 = 126 shows that each of these subnets can have 126 hosts.
Creating Three
Subnets
Beginning
with the previous example, consider an internetwork that requires three
subnets. The network in Figure 6-19 starts with the same 192.168.1.0 /24
address block. Borrowing a single bit would only provide two subnets. To
provide more networks, you change the subnet mask to 255.255.255.192 and borrow
2 bits. These 2 bits will provide four subnets. These networks are shown in
Table 6-16. The calculations follow.
Figure 6-19 Borrowing 2
Bits to Create Subnets
|
|
|
|
|
–
|
192.168.1.0
(/24)
|
Address:
|
11000000.10101000.00000001.00000000
|
|
0
|
|
|
|
||||||
|
|
|
|
|
|
255.255.255.0
|
Mask:
|
11111111.11111111.11111111.00000000
|
|
1
|
Router A
|
0
|
192.168.1.0
(/26)
|
Address:
|
11000000.10101000.00000001.00000000
|
|
|||
|
|
||||||||
|
|
||||||||
|
|
|
|
|
|
255.255.255.192
|
Mask:
|
11111111.11111111.11111111.11000000
|
|
|
|
|
|
|
|
|
2
1 192.168.1.64 (/26)
Address:
11000000.10101000.00000001.01000000
255.255.255.192Mask:11111111.11111111.11111111.11000000
2 192.168.1.128 (/26) Address: 11000000.10101000.00000001.10000000
255.255.255.192 Mask: 11111111.11111111.11111111.11000000
3 192.168.1.192 (/26) Address: 11000000.10101000.00000001.11000000

255.255.255.192 Mask: 11111111.11111111.11111111.11000000
Two
bits are borrowed
to
provide four subnets.
A 1 in these positions in the mask
means that these values are part of the network address.
Tidak ada komentar:
Posting Komentar